Return the largest consecutive integer in IEEE double precision.

format long e
f = flintmax

f =

     9.007199254740992e+15

This is 2^53.

Return the largest consecutive integer in IEEE single precision.

f = flintmax('single')

f =

    16777216

This is single(2^24).

Check the class of f.

class(f)

ans =

single

Above the value returned by flintmax('single'), not all integers can be represented exactly with single precision.

Return the largest consecutive integer in IEEE single precision.

f = flintmax('single')

f =

    16777216

This is single(2^24).

Add 1 to the value returned from flintmax.

f1 = f + 1

f1 =

    16777216

f1 is the same as f.

isequal(f,f1)

ans =

     1

Add 2 to the value returned from flintmax.

f2 = f + 2

f2 =

    16777218

16777218 is represented exactly in single precision while 16777217 is not.